#include <bits/stdc++.h>
using namespace std;
int main()
{
double n, m, t;
cin >> n; m = 0;
for (int i = 1; i <= n; i++)
{ cin >> t; m += t; }
cout << m << ' ';
cout <<fixed<<setprecision(5)<< m / n;
}
#include <bits/stdc++.h>
using namespace std;
int main() {
long long a, sum = 0, b;
cin >> a;
for (int i = 1; i <= a; i++) {
cin >> b;
sum = sum + b;
}
cout << sum << " " << fixed << setprecision(5) << sum * 1.0 / a;
}
共 3 条回复
#include <bits/stdc++.h> using namespace std; int main() { long long a, sum = 0, b; cin >> a; for (int i = 1; i <= a; i++) { cin >> b; sum = sum + b; } cout << sum << " " << fixed << setprecision(5) << sum * 1.0 / a; }
m 要输出整数